Lockpicks

Old Keyring

Old Keyring

I need to wait so long until Stella Clark released. So I afraid someone would discovered this synergy first.

First you need to be Preston Fairmont (Recommend) or Jenny Barnes (less effective)

Infinity and cheaper efficient Flashlight !

Note

AquaDrehz · 204
There's a step missing here. Why does the test always fail? If it is high enough to make Jenny consistently fail (5-6 shroud) then this isn't particularly great and you'd be better off with an Intel report. — DAAAN · 1
Agreed. It is guaranteed success on Shroud 1-2, and even Shroud 3-4 will sometimes be a pass for Preston (and fairly often for Jenny). — Death by Chocolate · 1484
The other issue to this combo is that it costs you an action to fail the test and reduce the shroud by 2. You would probably be better off just buying the clue with Lola and including an additional economy card in your deck (at least for Jenny). I could see Preston using the Old Keyring to get clues from 2 shrouds anyway. — The Lynx · 999
This doesnt work. At all. — JeremyL · 1
The -2 for the shroud only applies to the particular investigation. You can tell by the Investigate keyword and the fact the text says -2 FOR THIS INVESTIGATION. You cannot use Key Ring or Flashlight to somehow reduce the cost for assets like Lola Santiago — JeremyL · 1
@ JeremyL: it is possible, because there is a lightningbolt window in every test before and after commiting cards. During either of these you can trigger Lola's ability, while the shrowd is lowered. — Susumu · 382
Add in Drawing Thin to guarantee failure and generate cash for Lola. (^_~) — 4649matt · 7

Unbound Beast

Unbound Beast

Summoned Hound is set aside when Unbound Beast is drawn, but nothing indicates a way for the Summoned Beast to re-enter play. Does that mean that the Summoned Hound reappears once the Unbound Beast is subdued or is it effectively removed from the game?

unremb · 254
The summoned hound is removed from the game. As you say, there's nothing indicating that it comes back, so it doesn't. — SGPrometheus · 849
Seems like an oversight. This probably should have said "Otherwise, set an Investigator's Summoned Hound aside, out of play until this card leaves play..." — Othello · 2
I don't think that's an oversight. It's a deliberate design choice. Summoning is dangerous, when the summoned hound gets loose he's after you for daring to control him. So he starts munchin' on his summoner for revenge. And if you or someone else manage to defeat the hound - well, it's gone. — Csys · 1
It's not gone forever though, it's discarded, hence it can come back through deck cycling. — Éole · 14
(it's only a lost draw in that situation though, and an one-off, but still) — Éole · 14
The Unbound Beast is discarded - but the Summoned Hound remains out of play. — unremb · 254

Charles Ross, Esq.

Charles Ross, Esq.

Now, how does this work on Lola? If she is not in seeker role, would the discounts built up prior still usable/apply later? Or does it only apply on seeker/neutral items when she is a seeker?

Stretching it further, what if Ross is defeated/replaced (on Lola, or any investigator)? Would the discount built up still apply? Likely not, but if it does it would be really good, especially for Lola whose Ross easily dies to COI.

petercheungjr · 1
Since it's not an effect that you activate or trigger, I'm pretty sure she gets his discount no matter what role you're in. As for your other question, the discount only exists when he's in play generating it. There's no text indicating that he can affect the game from an out-of-play zone. — SGPrometheus · 849
I don't think it works with Lola. I think she would need to be in Seeker to take the Exhaust trigger. It would be the same as Beat Cop (one damage to an enemy at your location) imo and I doubt Lola can exhaust him to gain that damage. — The Lynx · 999
@TWWaterfalls, the op is asking about the scenario where they are a seeker, use Charles Ross' free triggered ability, then change to, say, Guardian and play a Guardian item. Is it discounted because Charles Ross was triggered by Lola the Seeker. For my 2 cents I think it works. — NarkasisBroon · 11
To complete my response I think SGPrometheus is correct on all counts. Except that his name seems to reference and inferior deathtrap of a starship, and should clearly be SGDaedalus — NarkasisBroon · 11
Yes, I agree with that. I wasn't thinking that far ahead. — The Lynx · 999
@NarkasisBroon I'm really just a fan of Greek mythology, but I get that a lot. — SGPrometheus · 849
If it ain't FAQ'ed, it plays as presented. That is, you can't stack the discount. — Blitheharrow · 51

A Baleful Welcome

A Baleful Welcome

Rules Question: Does picking 'investigate' turn off only the basic action, or also investigate actions on encounter cards and assets?

Similarly, does picking 'move' turn off shortcut, pathfinder, etc.?

kision314 · 2
Short answer: 1. yes, 2. no. Longer answer: if the chosen action category is being taken as a result of an Action ability--whether basic or activated from an asset, this treachery would "turn it off." If the action being taken is as a result of a fast card, a free action trigger ability, and suchlike--since it doesn't count as an action in the first place, this treachery does not turn it off. There might be a wrinkle if the card gives you an action in BOLD type, like on shortcut level 2 or summoned hound but i'm going to go out on a limb and say that you can take those actions as well. — Sycopath · 1
@Sycopath I think actually you cannot use Shortcut(2) or the hound, specifically because those use the bold action designator. If it said, "investigators cannot TAKE each chosen action..." I would agree with you, because that language specifically means you're taking one of your three basic actions, which those cards avoid. Because this says investigators can't "perform" the named actions, I take that to be a wider parameter which also covers free actions. — SGPrometheus · 849